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Indirection requires pointer operand
Indirection requires pointer operand









I think that thanks to our line-maps implementation, we can do the seeking quite more efficiently in terms of computation time. This is approximately what Clang (LLVM) does and it seems they can do it very fast by keeping a cache of buffers ever reopened. This is not trivial since we need to do it fast but still do all character conversions that we did when libcpp opened it the first time. Factoring out anything useful from libcpp would help to implement this. Care to handle charsets, tabs, etc must be taken into account. This is easy and fast but potentially memory consuming. Keeping the CPP buffers in memory and having in line-maps pointers directly into the buffers contents. Ideally, this should be more or less independent of CPP, so CPP (through the diagnostics machinery) calls into this when needed and not the other way around. Ifier We need to track the locations of X and r somehow.Ĭhanges in the parser to pass down the correct locations to the build_* functions.Ī location(s) -> source strings interface and machinery.

  • Changes on the build_* functions to handle multiple locations.
  • For non-preprocessed expr we need at least two locations per expr (beg/end).
  • This requires:įor each preprocessed token, we would need to keep two locations: one for the preprocessed location and another for the original location. This will fix the well-known limitation of the pretty-printer (see PR35441), PR35742, PR49152 and etc.). Please ask in for more information if you want to help to implement some of these projects.Ī) Printing the input expression instead of re-constructing it. The initializations are equivalent.Each point below is a mini-project on itself. The first pointer, proundup, is initialized using only the name of the function, while the second, pround, uses the address-of operator in the initialization. Once the function roundup is declared, two pointers to roundup are declared and initialized.

    indirection requires pointer operand

    This example shows equivalent ways of declaring a pointer to a function: int roundup( void ) /* Function declaration */ This example demonstrates that the result of applying the indirection operator to the address of x is the same as x: assert( x = *&x ) The value is assigned to the integer variable x: x = *pa The indirection operator ( *) is used in this example to access the int value at the address stored in pa. The result is stored in the pointer variable pa: pa = &a This statement uses the address-of operator ( &) to take the address of the sixth element of the array a. The following examples use these common declarations: int *pa, x Otherwise, the result is a pointer to the object or function designated by the operand. The result has the same effect as removing the & operator and changing the operator to a + operator. If the operand is the result of a operator, the & operator and the unary * implied by the operator aren't evaluated. The result isn't an lvalue, and the constraints on the operators still apply. If the operand is the result of a unary * operator, neither operator is evaluated and the result is as if both were omitted. The result is of type pointer to operand_type for an operand of type operand_type. The result of a unary dereference ( *) or array dereference ( ) operator. The operand must be one of these things:Īn lvalue that designates an object that isn't declared register and isn't a bit-field. The unary address-of operator ( &) gives the address of its operand.

    indirection requires pointer operand

    The pointer specifies an address not used by the executing program. The pointer specifies an address that's inappropriately aligned for the type of the object pointed to. (For example, an object that's gone out of scope or that's been deallocated.) The pointer specifies the address of an object after the end of its lifetime at the time of the reference. Here are some of the most common conditions that invalidate a pointer value: If the pointer value isn't valid, the result of the indirection operator is undefined. If it points to an object, the result is an lvalue that designates the object. If the operand points to a function, the result is a function designator. The result of the indirection operator is type if the operand is of type pointer to type.

    indirection requires pointer operand

    The type of the result is the type that the operand addresses. The result of the operation is the value addressed by the operand that is, the value at the address to which its operand points.

    indirection requires pointer operand

    The unary indirection operator ( *) accesses a value indirectly, through a pointer.











    Indirection requires pointer operand